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Wysłany: Czw 7:38, 06 Sty 2011 Temat postu: mbt italia On the mean free path λ ^ -= 1 ( |
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On the mean free path λ ^ -= 1 / (√ 2πd ^ 2n) of √ 2
2. For the same ideal gas molecules, ==, and cos8 values can be positive or negative, on average: = 0, then = √ 2, = 1 / (. N). Second, the collision of two molecules can be regarded as the equivalent mass m '= m1m2 / (ml + m2) of the monomer movement. Because the same kind of ideal gas molecules m. : M: = m, then m = m / 2, be substituted into the Maxwell speed distribution,[link widoczny dla zalogowanych], calculated the average rate formula, then the port = √ 8KT / (~ m):,[link widoczny dla zalogowanych], / 22 ~, 8K D / (m ) = √ 2 into (1) correction factor can also be obtained. Statistical average of the relative rate of 3 relative rate, the calculation is not so simple. We always want to have closer and the actual results. This way of thinking to find a certain speed range as part of the risk of emergence. Obtained rate distribution function. And satisfy the normalization condition. Is composed of the Maxwell speed distribution. Export in equilibrium mixture of ideal gas molecules in the distribution function of the relative velocity, thus proving that the gas molecules relative to the same average rate of u. And the resulting mean free path. Set in equilibrium by the molecular mass of ideal gas, respectively m. And m2, a mixture of two gases. By the Maxwell speed distribution shows: the first part of a gas in any speed. ~. + Dv. Probability interval for the dW. == () A / ~ exp (a). Similarly, any part of the second gas velocity ~ d2 interval at the chance to dWz =, (\112 Wuhan University of Hydraulic and Electric since 1997, child labor rate of the two gas distribution is independent of each other, the jump they exist in two intervals of the probability of upward mobility for the dWdW =()()· one,[link widoczny dla zalogowanych]!!;) DIdexp (2 ( 2) a --- ji a, dI2L because the relative motion of two molecules rate D: \gas molecule mass motion velocity Ⅱ = mll + m2 \= Hc-mI / (ml +2). (2d) m + mzi = (t + m :)\, and is seeking (2) the dld2 and d \Distribution Law by the djd2 = Jdudv, where J is Jacobian. in three-dimensional space with the component type that is ddv2dIdr2ydr1dvz = Lfd \/ () f () d \= gas molecules relative speed distribution, Maxwell distribution law has the same form of mathematical expression,[link widoczny dla zalogowanych], is iE distribution function. from the normal distribution function shows that when m = 』Bu = o, 2a: 1, the = go, then this becomes 』e. d =, and the resulting distribution of the relative rate of speed distribution of mass satisfy the normalization condition. Let A = control, then I, (u) d =』 () 'exp (a duI = j (xp 【I (+ Chuan 1dvr.rdd mouth:: (AI) / (I /,/)= 1 Similarly JvJ = l_ so dldv2 = dudv. (2f) to (2e), (2f)-type into (2) have dI2 = f (port 1), (2) dvldv2 = (Ya mira2J3/2e arsenic c a hairpin) () · exp [a) d \mI +2), finishing on the type may dW () 31Zexp (a + m2m2 / (ml +2) 2KT). One Similarly f () dn = 1. this show,[link widoczny dla zalogowanych], (u) ideal for our requirements the relative speed distribution of gas. and can thus calculate the average of any two molecules relative rate; as) du = √: f a 8KTr :(;}+;。, mIm2, for the same ideal gas molecules in equilibrium have the same arithmetic average rate ;=;=;, so;, = √ j; this can get: to n, i = 1 / (Ji). These studies can be used in university physics teaching
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